论文部分内容阅读
50％(V/V)醋酸的苯胺-醋酸试剂,在50℃加热10分钟,使木糖显红色,而葡萄糖不显色。木糖显色产物的吸收光谱示于图1,480毫微米的吸光度和木糖存在量之间的关系示于图2。阿拉伯糖的情况和木糖相似。于是选定苯胺:冰醋酸:水=3:10:7(体积比)的配方用作六碳糖存在下鉴别五碳糖的试剂。鉴别手续确定为:取适当稀释的待测液0.5毫升放入试管内,加该试剂5毫升,摇匀,置于50℃恒温水浴中显色10分钟,移置自来水中迅速冷却,有五碳糖存在即显红色,颜色深浅代表存在量高低。在此条件下某些六
Aniline-acetic acid reagent at 50% (v / v) acetic acid was heated at 50 ° C for 10 minutes to make the xylose red and not glucose. The absorption spectrum of the xylose color-producing product is shown in Fig. 2 as a relationship between the absorbance at 1,480 nm and the amount of xylose present. The case of arabinose is similar to that of xylose. So choose aniline: glacial acetic acid: water = 3: 10: 7 (volume ratio) formula for the identification of five-carbon sugar in the presence of six-carbon sugar reagent. Identification procedures identified as: Take appropriate dilution of the test solution 0.5 ml into the test tube, add the reagent 5 ml, shake, placed in 50 ° C water bath for 10 minutes, relocated in tap water quickly cooled, five carbon The presence of sugar that is significantly red, the color depth of the level of presence. Under these conditions some six