Synthesis, characterization and magnetism of μ-chloranilato bi-nuclear chromium (III) complexes

来源 :Chinese Journal of Chemistry | 被引量 : 0次 | 上传用户:suzengbiao
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Five new chloranilato-bridged binuclear chromium (III) complexes have been synthesized and identified as [Cr2(CA)L4]-(ClO4)4[L denotes 5-methyl-1,10-phenanthroline (Me-phen); 2,9-dimethyl-1, 10-phenanthroline ( Me2-phen); 5-chloro-1,10-phenanthroline(Cl-phen); diaminoethane (en) or 1,3-diaminopropane (pn)], where CA represents the dianion of chloranilic acid. Based on elemental analyses, molar conductivity and magnetic moment of room-temperature measurements, and IR and electronic spectral studies, it is proposed that these complexes have CA-bridged structures and consist of two chromium (III) ions, each in an octahedral environment. The complexes [Cr2(CA)(Me-phen)4](ClO4)4(1) and [Cr2(CA)(Me2-phen)4](ClO4)4(2) were further characterized by variable temperature (4.2-300 K) magnetic susceptibility measurements and the observed data were successfully simulated by the equation based on the spin Hamiltonian operator, , giving the exchange parameter J = -7.8 cm-1 for (1) and J= -6.5 cm*1 for (2). This result Five new chloranilato-bridged binuclear chromium (III) complexes have been synthesized and identified as [Cr2 (CA) L4] - (ClO4) 4 [L 5-methyl-1,10-phenanthroline 5-chloro-1,10-phenanthroline (Cl-phen); diaminoethane (1,3) -diaminopropane (pn)], where CA represents the dianion of Based on elemental analyzes, molar conductivity and magnetic moment of room-temperature measurements, and IR and electronic spectral studies, it is proposed that these complexes have CA-bridged structures and consist of two chromium (III) ions, each in an The complexes [Cr2 (CA) (Me-phen) 4] (ClO4) 4 (1) and [Cr2 (CA) (Me2-phen) 4] (ClO4) 4 (2) were further characterized by variable temperature (4.2-300 K) magnetic susceptibility measurements and the observed data were successfully simulated by the equation based on the spin Hamiltonian operator, giving the exchange parameter J = -7.8 cm -1 for (1) and J = -6.5 cm * 1 fo r (2). This result
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