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一项工程,甲队独做24天完成,乙队独做要比甲队多8天完成,两队合做中途乙队调离该工程若干天,开工15天两队才把该工程完成。开工后乙队中途离开了多少天? [解法一] [(124+124+8)×15-1]÷124+8=3(天) [解法一]是按“假设思路”来分析的。假设乙队中途不调离且与甲队合作15天,那么两队多完成工作总量的332,由于实际只有甲队做了15天,乙队未做满15天,所以多完成的332是假设
A project, Team A alone to do 24 days to complete, Team A alone to do more than Group A eight days to complete, the two teams together to move away from the team a number of days away from the team, started 15 days before the completion of the two teams of the project. How many days did the team leave midway after starting work? [Solution 1] [(1 24 + 1 24 + 8) × 15-1] ÷ 1 24 + 8 = 3 According to “hypothetical train of thought” to analyze. Assuming the team does not transfer halfway and team 15 days of cooperation, then the two teams to complete the total work more than 3 32, because the actual team only 15 days, team B did not do 15 days, so more complete The 3 32 is assumed