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时钟指针问题是一类趣味性较强的几何、代数综合题.这类问题看似复杂,但究其特征不难看出,从解法上讲属于应用题中的环形追及问题:我们把钟表盘圆周看成路程为360°的一个圆环,时钟分针每小时(即60分)走一圈(即旋转360°),所以它每分钟走360°/60=6°;时针每小时(即60分)走1/12圈(即旋转360/30°),所以它每分钟走30°/60=(1/2)°.因此,分针与时针的速度差为每分钟
The clock hand problem is a type of geometric and algebraic synthesis problem with a strong interest. This type of problem may seem complicated, but it is not difficult to see that the characteristics are not difficult to see. From the solution point of view, the ring in the application problem is to catch up with the problem: we put the clock dial circumference Consider a circle with a 360° turn, the clock minute hand takes one hour (ie, 60°) to go around (ie rotates 360°), so it goes 360°/60=6° per minute; hourly hourly (ie 60 points ) Take 1/12 turn (that is rotate 360/30°), so it walks 30°/60=(1/2)° per minute. Therefore, the speed difference between minute hand and hour hand is every minute.