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1题目正方形ABCD中,点E在BC边上,AE⊥EF,EF交∠BCD外角平分线于F.(1)如图1,当E是BC中点时,求证:AE=EF;(2)如图2,当E不是BC中点时,(1)中结论还成立吗?若成立,请给予证明。这是学生在八年级学习正方形后做过的一道同步练习题,在新课学习时,证明线段相等的常见方法有1利用三角形全等的性质;2同一三角形中等角对等边;3通过等量代换,将问题转化为上述形式。而在中考复习时,学生所掌握的知识与方法更多,证明两条线段
1 subject square ABCD, the point E in the BC edge, AE ⊥ EF, EF cross-BB outer angle bisecting line F. (1) As shown in Figure 1, when E is BC midpoint, verify: AE = EF; ) As shown in Figure 2, when E is not BC midpoint, (1) the conclusion is still true? If yes, please give proof. This is a synchronous exercise that students have made since they studied the square in the eighth grade. Common ways to prove that the line segments are equal when learning a new lesson are: 1 using the congruent nature of triangles; 2 the same angle with the equilateral triangle; 3 Volume substitution, the problem into the above form. In the exam review, students have more knowledge and methods to prove that two lines