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本刊八五年第十期发表的《一常见三角公式的另一证法》,构思新颖,读后深受启发,本文再提供一种新的证法。题:△ASC中,有tgA十tgb+tgC==tgAtgBtgC。证;作△ABC的外接圆。
The “Another Trivial Formula of a Common Triangle Formula” published in the tenth issue of the journal in 1985 was a novel idea. After reading it, it was deeply inspired. This article provides a new proof method. Problem: In ASC, there are tgA ten tgb+tgC==tgAtgBtgC. Certificate; make a circumcircle of ABC.