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本刊今年第四期P22例12:△ABC中,若sinC=(sinA+sinB)/(cosA+cosB),则△ABC是( ), (A)等腰三角形; (B)正三角形; (C)直角三角形; (D)锐角三角形原解的思考是:选择支中有
In this year’s fourth issue of P22 Case 12:△ABC, if sinC=(sinA+sinB)/(cosA+cosB), then △ABC is (), (A) isosceles triangle; (B) is a regular triangle; ( C) right-angled triangle; (D) the original solution of the acute-angled triangle is: