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图1是普通教材介绍的演示断电瞬间,灯泡突然发出强闪光,然后才熄灭的自感电路。却有不少教师要做成功这个演示,觉得很难。因为即使已满足了教材所述条件,使原来通过线圈的电流 I_2比原来通过灯泡的电流 I_1大,也不一定能使灯泡熄灭前短时发出更强的光。其原因是除需 I_2>I_1外,显然还有需兼顾线圈电感量等条件。那么,什么条件的电感线圈才适用于演示?这里向大家介绍一个我们由理论推导得出的简易公
Figure 1 is a demonstration of common textbook demonstration power moment, the light bulb suddenly issued a strong flash, and then extinguished the self-inductance circuit. There are many teachers to do this demonstration of success, I find it very difficult. Because even if the conditions described in the textbook are satisfied, the original current I_2 passing through the coil is larger than the original current I_1 passing through the bulb, and it is not always possible to make the light bulb emit stronger light shortly before the light bulb goes out. The reason is that in addition to I_2> I_1, apparently need to take into account the coil inductance and other conditions. So, what conditions of the inductor is suitable for demonstration? Here to introduce a simple reason we derived from the theory