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1试题呈现(天津卷第25题)已知抛物线y=x~2+bx-3(b是常数)经过点A(-1,0)。(1)求该抛物线的解析式和顶点坐标;(2)P(m,t)为抛物线上的一个动点,P关于原点的对称点为P′。①当点P′落在该抛物线上时,求m的值;②当点P′落在第二象限内,P′A~2取得最小值时,求m的值。2特色解读及教学导向分析本题呈现方式自然朴实,叙述过程简明扼要,作为中考压轴题,具有较好的教学导向作用,值得深入思考,亦可作为初高中衔接的重要素材来达到承前启
1 Question Presentation (Tianjin Volume 25) It is known that the parabola y = x ~ 2 + bx-3 (b is a constant) passes through the point A (-1,0). (2) P (m, t) is a moving point on the parabola, P is the symmetry point on the origin P ’. When the point P ’falls on the parabola, find the value of m; When the point P’ falls within the second quadrant, P’A ~ 2 to obtain the minimum, find the value of m. 2 characteristics of interpretation and teaching-oriented analysis of the problem is simple and natural way of presenting the narrative process concise, as the finale of the test, with good teaching-oriented role, it is worth pondering, can also be used as an important source of high school convergence to achieve Chengqianqi