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一、直角三角形斜边上中线的性质和拓展性质直角三角形斜边上的中线等于斜边的一半.如图1.在Rt△ACB中,∠ACB=90°,D为AB的中点,则CD=1/2AB.拓展结论1直角三角形的三个顶点落在以斜边上的中点为圆心,中线长为半径的圆上.拓展结论 2直角三角形斜边上的中线把直角三角形分成两个等腰三角形,它们的腰相等,面积也相等,而且它们的顶角互补,底角互余,一个等腰三角形的顶角等于另一个等腰三角形底角的2倍.二、性质及拓展结论的应用
First, the right triangle hypotenuse on the nature and expansion of the nature of the hypotenuse of the right triangle on the hypotenuse of the midline equal to half the hypotenuse shown in Figure 1. In Rt △ ACB, ∠ ACB = 90 °, D is the midpoint of AB, then CD = 1 / 2AB. DISCUSSION CONCLUSION 1 The three vertices of a right-angled triangle fall on a circle centered on the midpoint of the hypotenuse with a long radius of the medial line. CONCLUSION 2 The midline on the hypotenuse of a right triangle divides the right triangle into two An isosceles triangle, their waist is equal, the area is also equal, and their vertex is complementary, the bottom corner of each other, an isosceles triangle vertex equal to 2 times the angle of the other isosceles triangle 2. Second, the nature and development Conclusion of the application