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在分数问题中常常会遇到含有这样条件的题:甲数的2/3与乙数的3/5相等。此类条件转化的方法有很多,其中可以将它们已转化为同分子分数:甲数的6/9与乙数的6/(10)相等。从而得到甲数的1/9与乙数的1/(10)相等,即把甲数分为9等份,乙数分为10等份,则这样的每一等份相等。由此,便很容易找到突破口,使问题巧妙地得到解决。下面我们提供几个例子来进一步加以说明。
Frequently, you encounter problems that include such conditions as 2/3 of the number of A’s and 3/5 of the B-number. There are many ways to convert such conditions, where they can be converted into the same molecular fraction: 6/9 of a number equals 6 / (10) of B. Thus, one-ninth of the number of aces is equal to one tenth of the number of B’s, ie, dividing the number of nails into nine equal parts and dividing the number of B’s into ten equal parts. As a result, it is easy to find a breakthrough to solve the problem skillfully. Below we provide a few examples to further illustrate.