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同一个题目,尤其是综合题,有的人拿到会迅速得解,有的人却一筹莫展,只能望题兴叹。究其因,固然不能一概而论,但是,善于将题目的条件、结论等价变通或重组整合,不失解综合题之良策。现撷2001年中考题几例略述,供参阅。例1 在Rt△ABC中,∠ACB=90°,AB=53、BC=a,AC=b,且a>b,若a,b分别是二次函数y=x2-(2k+1)x+k2-2的图象与x轴两个交点的横坐标,求a,b的值。(天津市中考题)分析摆条件:(1)∠ACB=90°,AB=53;(2)BC>AC,BC、AC分别是y=x2-(2k+1)x+k2-2的图象与x轴两个交点的横坐标:
The same topic, especially the comprehensive question, some people will quickly get solution, and some people are unable to do anything, can only hope to sigh. The reason for this cannot be generalized, but it is adept at reconciling and integrating the conditions and conclusions of the topic, without losing the solution to the comprehensive question. Several examples of the 2001 mid-term exam questions are outlined for your reference. Example 1 In RtΔABC, ∠ACB=90°, AB=53, BC=a, AC=b, and a>b, if a,b are quadratic functions y=x2-(2k+1)x respectively. The coordinates of the +k2-2 image and the x-axis are the abscissas. Find the values of a and b. (Tianjin Intermediate Test Questions) Analyze the pendulum condition: (1) ∠ACB=90°, AB=53; (2) BC>AC, BC, AC are y=x2-(2k+1)x+k2-2 The abscissa of the intersection of the image and the x axis: