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本文在分析乙烯-α-烯烃共聚物序列结构时,把代表共单体反接单元的亚甲基(CH_2)βγ和γδ分别归属给了二元组VV和三元组EEV。与此同时,CH_2-δδ和δδ~+归属给了二元组EE。表征乙烯长序列的CH_2-δ~+δ~+分属二元组EE和三元组EEE,对应峰强度在EE和EEE之间的分配是处理序列分布的关键。在本文中运用序列结构的Bovey关系和Randall统计进行演算,求得了修正值△的数学表达式,严格解和近似解。在规则链条件下得到的近似解与G.J.Ray的结果完全相同。当共单体含量较少时,谱峰强度Iδ~+δ~+的分配接近相等。 在二元组和三元组的水平上,乙烯-α-稀烃共聚物的~(13)C NMR谱中共有十三个峰,属于CH_2的有十个,属于CH的有三个。利用这些谱峰的强度数据可以建立一套计算公式,由此提供共聚物序列结构的全部信息。因此这是一个研究乙烯-α-烯烃共聚物序列结构的普适方法。
In this paper, methylene (CH_2) βγ and γδ, which represent the comonomer units, were assigned to the binary group VV and the triple EEV respectively when analyzing the ethylene-α-olefin copolymer sequence structure. At the same time, CH 2 -δδ and δδ ~ + belong to the binary EE. CH 2 -δ ~ + δ ~ +, which characterizes the long sequence of ethylene, belongs to EE and triple EEE. The distribution of corresponding peak intensities between EE and EEE is the key to process sequence distribution. In this paper, the Bovey relation of sequence structure and Randall’s statistics are used to calculate the mathematical expression, the strict solution and the approximate solution of the correction value △. The approximate solution obtained under the rules of the chain is exactly the same as that of G.J. Ray. When the monomer content is small, the distribution of peak intensity Iδ ~ + δ ~ + is nearly equal. At the binary and triplet levels, there are thirteen peaks in the ~ (13) C NMR spectrum of the ethylene-α-olefin copolymer, ten for CH_2, and three for CH. Using the intensity data for these spectral peaks, a set of formulas can be established, thereby providing complete information on the structure of the copolymer sequence. Therefore, this is a universal method for studying the sequence structure of the ethylene-α-olefin copolymer.