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一、问题如图1所示为理想变压器 T,其原副线圈中分别连接两只规格完全相同的灯泡 L_1、L_2,开关 S 闭合时,两者均能正常发光,问开关 S断开后,L_1、L_2的亮度如何变化?很显然,开关 S 断开后, L_2熄灭;但对 L_1的亮度变化却有两种不同的观点.观点1:L_1熄灭.因为开关 S 断开后,副线圈中的电流 I_2=0,故原线圈中电流 I_1=n_2/n_1I_2=0.
First, the problem is shown in Figure 1 for the ideal transformer T, the original secondary coil were connected to two bulbs L_1, L_2 exactly the same size, when the switch S is closed, both can light normally, ask the switch S is disconnected, How does the brightness of L_1 and L_2 change? Obviously, after the switch S is turned off, L_2 goes out; but there are two different views on the brightness change of L_1. Point of view 1: L_1 is extinguished. Because the switch S is turned off, the secondary coil is turned off. The current I_2=0, so the current I_1=n_2/n_1I_2=0 in the original coil.