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两个8脚IC组成的稳压器电路可把锂电池的3V输出电压转换成5V,并提供高达100mA的负载电流(见附图).它不靠电感器和变压器工作,静态消耗电流仅为200μA.当输入电压V_(in)=3V时,如果带100mA负载,其效率为81%;如果带20mA负载,其效率为84%.它的效率能随V_(in)的降低而增加.比如,当V_(in)=2.7V(该电池在大部分工作寿命期间的负载输出电压)时,40mA负载电流的效率为90%.锂电池(Duracell公司2/3-A号电池DS123A)的输出电压用大电流充电泵IC1增加一倍.肖特基二极管D1用来保证该电路的启动.D1不会影响效率,因为在正常工作时负载电流不从中流过.IC2是线性稳压器,当负载电流
The regulator circuit of two 8-pin ICs converts the 3V output voltage of a lithium battery into 5V and provides a load current of up to 100mA (see the photo). It does not operate with inductors and transformers and consumes only 200μA. The efficiency is 81% with a 100mA load at input voltage V_ (in) = 3V and 84% with a 20mA load. Its efficiency can increase with decreasing V in. For example , The efficiency of the 40mA load current is 90% when V in (in = 2.7V, the load output voltage of the battery during most of its operating life.) The output of a lithium battery (Duracell 2/3-A battery DS123A) The voltage is doubled with the high-current charge pump, IC1. The Schottky diode, D1, is used to guarantee the startup of the circuit. D1 does not affect efficiency because the load current does not flow in normal operation. IC2 is a linear regulator, Load current