论文部分内容阅读
分子式为C_6H_8O的哪一个化合物与图E-11符合? 取谱条件: 溶剂:CDCl_3(δ77.2三重峰) 浓度:50V/V％温度:28℃测定频率:22.63MHz 去偶:上——~1H偏共振去偶(500次) 下——~1H宽带去偶(100次) [解答]C_6H_8O含有三个双键当量。在~(13)C谱中找到一个羰基(δ198.65)以及一个C=C键(δ150.6及129.85)。还余下一个双键与三个次甲基(δ38.2,25.75及22.95)。总结起
Which one of the compounds of the formula C_6H_8O is in accordance with Figure E-11? Conditions for the determination: Solvent: CDCl 3 (δ77.2 triplet) Concentration: 50 V / V% Temperature: 28 ° C Measurement frequency: 22.63 MHz Decoupling: 1H Partial Resonance De-even (500 times) - ~ 1H Wideband Dispense (100 times) [Answers] C_6H_8O contains three double-bond equivalents. A carbonyl group (δ198.65) and a C = C bond (δ150.6 and 129.85) were found in ~ (13) C spectrum. There was also one double bond and three methine residues (δ 38.2, 25.75 and 22.95). Sum up