论文部分内容阅读
用差热分析法研究了LaCl_3—RbCl体系,得到了它们的熔度图。在LaCl_3—RbCl体系中生成了三个化合物。第一个化合物的组成相当于3RbCl·LaCl_3,熔点695℃;第二个化合物的组成相当于RbCl·3LaCl_3,其转熔点P_1的温度为624°;第三个化合物组成相当于3RbCl·2LaCl_3,其转熔点P_2的温度为625℃。RbCl·3LaCl_3与3RbCl·2LaCl_3之间形成低共熔体,其组成为46摩尔%LaCl_3,熔点为562℃。RbCl与3RbCl·LaCl_3之间形成的低共熔体其组成为16摩尔%LaCl_3,熔点为580℃。
The differential thermal analysis of LaCl_3-RbCl system, obtained their melting diagram. Three compounds were generated in LaCl_3-RbCl system. The composition of the first compound is equivalent to 3RbCl? LaCl ?, the melting point is 695C; the second compound has a composition corresponding to RbCl.3LaCl ?, the temperature of the melting point P? Is 624; the third compound is equivalent to 3RbCl.2LaCl? The temperature of the melting point P_2 is 625 ° C. A low eutectic was formed between RbCl.3LaCl_3 and 3RbCl.2LaCl_3, with a composition of 46 mol% LaCl_3 and a melting point of 562 ° C. The eutectic formed between RbCl and 3RbCl? LaCl? Has a composition of 16 mol% LaCl? And a melting point of 580C.