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A 题组新编1 .在△ ABC中 ,∠ C =2∠ B.( 1 )则 sin3Bsin B等于 ( ) .( A) ab ( B) ba ( C) ac ( D) ca( 2 )则边 c等于 ( ) .( A) 2 bsin C ( B) 2 bcos B( C) 2 bsin B ( D) 2 bcos C( 3)求证 :c2 - b2 =ab.( 4 )已知△ ABC三边组成一个公差为 1
The new group A is 1. In △ ABC, ∠ C = 2 ∠ B. (1) Then sin3Bsin B is equal to (). (A) ab (B) ba (C) ac (D) ca (2) is the edge c is equal to (). (A) 2 bsin C (B) 2 bcos B (C) 2 bsin B (D) 2 bcos C (3) Proof: c2 - b2 = ab. (4) Known △ ABC three sides compose One tolerance is 1