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试题1(安徽卷,理科第2题)设集合 A={x||x-2|≤2,x∈R},B={y|y=-x~2,-1≤x≤2),则_R(A∩B)等于( ).A.R B.{x|x∈R,x≠0} C.{0} D.试题特点:本题是集合部分的典型题目,以不等式和二次函数为载体考查集合的运算,搞不清楚集合 B 的含义是导致错误的主要原因之一.选项 A 与 D、B 与 C 之间的互斥关系,为解决问题提供了更广阔的思路.思路分析:1.选项 A 与 D、B 与 C 之间有互斥关系,据此特点,易排除A、D 选项,观察知 0∈A∩B,故选 B.2.由于_R(A∩B)=_RA∪_RB,集合_RA 表示数轴上到2
Problem 1 (Anhui Volume, Science Question 2) Let set A = {x || x-2 | ≦ 2, x∈R}, B = {y | y = -x ~ 2, -1≤x≤2) , Then _R (A∩B) equals () .AR B. {x | x∈R, x ≠ 0} C. {0} D. Test questions feature: This question is a typical part of the collection, with inequality and quadratic Function as a vector to test the operation of the set, do not understand the meaning of the set B is one of the main causes of error.Options A and D, B and C mutually exclusive relationship, to solve the problem provides a broader idea. Analysis: 1. Options A and D, B and C are mutually exclusive relations, according to this feature, easy to rule out A, D options, observation 0 ∈ A ∩ B, so choose B.2. As _R (A ∩ B) = _ RA∪_RB, set _RA said on the axis to 2