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一般地,在一次函数y=kx+b中,令y=0,则得kx+b=0,这就是一元一次方程,它的根就是一次函数y=kx+b的图象与x轴交点的横坐标.一元一次不等式kx+b>0(或kx+b<0),可以看作是y=kx+b取正值(或负值)时的特殊情况,它的解集可以看作一次函数y=kx+b相应的自变量x值的取值范围.两直线交点的坐标,就是由这两条直线的解析式组成的二元一次方程组的解.下面以2005年中考题为例说明.例1(徐州市)已知一次函数y=ax+b(a、b是常数),x与y的部分对应值如下表:
Generally, in the first-order function y=kx+b, if y=0, then kx+b=0. This is a univariate equation whose root is the intersection of the image of the first function y=kx+b and the x-axis. The abscissa. A one-time inequality kx+b>0 (or kx+b<0) can be considered as a special case when y=kx+b takes a positive (or negative) value. Its solution set can be considered as The range of values of the x-value of the independent function y=kx+b corresponding to the primary function. The coordinates of the intersection of the two straight lines is the solution of the binary equations composed of the analytical expressions of the two straight lines. The following is the title of the 2005 examination. For example, Example 1 (Xuzhou City) has a known function y=ax+b (a and b are constants). The corresponding values of x and y are shown in the following table: