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设n个数据x1,x2,……,Xn的平均数为x,则其方差为S2=1/n[(x1-x)2+(x2-x)2+…+(xn
Let the average number of n data x1, x2, ..., Xn be x, then the variance is S2=1/n[(x1-x)2+(x2-x)2+... +(xn