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若点E是△ABC的中线AD和CF的交点,则点E就是△ABC的重心。根据重心性质有DE/AE=1/2,再由BF=AF,可得比例式
If point E is the intersection point of the midline AD and CF of ΔABC, point E is the center of gravity of ΔABC. According to the nature of gravity, there is DE/AE=1/2 and then BF=AF.