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众所周知,若G为△ABC的重心,则有AG2+BG2+CG2=31(a2+b2+c2).于是,我们思考,对于△ABC的其它各心会有怎样的结果呢?
As we all know, if G is the center of gravity of △ABC, then there is AG2+BG2+CG2=31(a2+b2+c2). So, we think, what kind of result will it have for the other hearts of △ABC?