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对于含多个字母的因式分解题,大多数学生都不知如何下手求解,在此,本人给出一种比较实用的方法,那就是以题中某个字母为主元,其他字母看成是常数,这样将多元问题变为一元问题,问题便轻易解决,下面举例说明.例1分解因式2x~2-5xy+2y~2+7x-5y+3.解:视x为未知元,变形,则有:原式=2x~2+(7-5y)x+(2y~2-5y+3)=2x~2+(7-5y)x+(y-1)(2y-3)=[2x-(y-1)][x-(2y-3)]
For multi-letter factorization problem, most students do not know how to get started, here, I give a more practical way, that is to say in a letter as the main element, the other letters as Is a constant, so that the multivariate problem into a dollar problem, the problem will be easily solved, the following example .Example 1 factorization factor 2x ~ 2-5xy + 2y ~ 2 + 7x-5y + 3. Solution: As the unknown element x, (2y-2-5y + 3) = 2x ~ 2 + (7-5y) x + (y-1) (2y-3) = [ 2x- (y-1)] [x- (2y-3)]