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文[1]中有一道关于“得票高低”的初二竞赛试题(简称题[1]),其题目与解答如下:题目学生会选举有四个候选人A,B,C,D,已知D得票比B得票多,A、B得票之和超过C、D得票之和,A、C得票之和与B、D得票之和相等,则四人得票数由高到低的排列次序是().(A)A,D,C,B(B)D,B,A,C(C)D,A,B,C(D)A,D,B,C答:(D).解用圆形图表示,因A,C得票之和与B,D得票之和相等,作一直径分圆为两半,上部分B,D;下部为A,C;已知D得票比B得票多,画得扇形D大于扇形B;由A,B得票之和超过C,D得
The first and second competition questions (“Questionnaire [1]”) in the text [1] are as follows: Question The student union elects four candidates A, B, C and D, Knowing that D has more votes than B, the sum of A and B votes exceeds C and D, and the sum of A and C votes equals the sum of B and D votes, then the rank order of the four votes from highest to lowest is (A) A, D, C, B (B) D, B, A, C (D) A, B, C A circular chart, because A, C sum of votes and B, D and the sum of votes equal to make a diameter circle in half, the upper part of B, D; the lower part of A, C; More, painted fan D is greater than the fan-shaped B; by A, B votes and more than C, D too