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一、引言用溶度法研究稀土元素氯化物(LnCl_3)-脲(Urea)-水三元体系,国外已有人做了大量工作。据文献报道,在稀土元素氯化物-脲-水体系中,得到了大量稀土元素氯化物与脲(及水)所形成的复合物。我们注意到:所有稀土元素氯化物与脲几乎都有1∶6和1∶4的复合物生成,唯CeCl_3与CO(NH_2)_2只有1∶6而无其它复合物产生。这引起了我们的兴趣,为了探讨这个问题,我们进行了CeCl_3-CO(NH_2)_2-H_2O体系在0℃和25℃时的研究。
I. INTRODUCTION It is known that a lot of work has been done abroad by the solubility method to study the ternary system of LnCl_3-urea (Urea) -water. It has been reported in the literature that a large amount of complexes of rare earth chloride with urea (and water) are obtained in the rare earth chloride-urea-water system. We note that almost all of the rare earth chlorides and ureas have a 1: 6 and a 1: 4 complex, only CeCl 3 and CO (NH 2) 2 are only 1: 6 and no other compounds are produced. This caused our interest. In order to explore this issue, we carried out a study of CeCl_3-CO (NH_2) _2-H_2O system at 0 ℃ and 25 ℃.