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题目如图1所示,在x轴固定着两个等电荷量同种点电荷+Q,它们之间的距离为2L,b点为两电荷连线中点,a、b两点关于左侧+Q对称,c、d两点到x轴的距离也为L。规定无穷远处电势为0,则下列判断正确的是()A.c、d两点场强相同B.电荷-q从c点沿虚线移动到d点,电荷-q的电势能不变C.c点电势等于d点电势D.a、b、c、d四点的场强大小关系为E_c=E_d>E_a>E_b原解理解等量同种电荷电场的几何形状,由对
The subject is shown in Figure 1, the x-axis is fixed with two equal charge of the same type of charge + Q, the distance between them is 2L, b points for the two charge connection midpoints, a, b two points on the left + Q symmetry, c, d two points to the x-axis distance is also L. The provisions of the potential is infinite at 0, then the following judgment is correct () Ac, d two points the same field strength B. Charge-Q from point c along the dotted line to move to d, the charge-q potential can be unchanged Cc point potential Equivalent to the d-point potential Da, b, c, d four-point field strength of the relationship between E_c = E_d> E_a> E_b original solution to understand the same electric field of the same type of electric field geometry,