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题求过定点P(2,3)且在两轴上截距相等的直线的方程。解若设两截距为a,则有:x/a+y/a=1,即 x+y=a。因为直线过(2,3)点,所以2+3=a,即a=5。因此所求的方程为x+y=5。上面的解法见日本(竹世)部贞市郎编《几何学辞典》中译本第3498题。
The equation for the straight line over the fixed point P(2,3) and the intercepts on both axes are equal. If the solution is set to two intercepts, a: x/a+y/a=1, that is, x+y=a. Because the line passes through (2,3) points, 2+3=a, that is, a=5. Therefore, the required equation is x+y=5. See the 3498 question in the Chinese translation of the “Geometry Dictionary” published by the Department of Geography in Japan.