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以双四唑胺(H2bta)、NdCl3.6H2O、KOH为原料,用水热法合成了1个一维异核的Nd3+配合物[KNd(bta)2(H2O)6]·H2O。通过X-射线单晶衍射、元素分析、红外光谱对该配合物进行了结构表征。该化合物属于单斜晶系,P21/m空间群。每个Nd3+与2个来自bta2-离子的4个氮原子和5个水分子形成了1个盖帽的四方双锥,通过bta2-和水分子桥联配体把Nd3+和K+连接成一维链状结构,链与链之间通过O-H…N和N-H…O氢键作用形成三维超分子结构。紫外吸收光谱和荧光光谱表征结果显示该配合物的水溶液在292和412 nm表现出双四唑胺的特征吸收峰和荧光发射特征峰。
A one-dimensional heteronuclear Nd3 + complex [KNd (bta) 2 (H2O) 6] · H2O was synthesized by hydrothermal method using bis-oxazole (H2bta), NdCl3.6H2O and KOH as raw materials. The complex was characterized by X-ray single crystal diffraction, elemental analysis and infrared spectroscopy. The compound belongs to the monoclinic space group P21 / m. Each Nd3 + forms a capped tetragonal bipyramid with two nitrogen atoms from bta2- and five water molecules, linking Nd3 + and K + into a one-dimensional chain structure via a bta2- and water molecule bridging ligand The three-dimensional supramolecular structure is formed by the interaction of OH ... N and NH ... O hydrogen bonds between chains. UV absorption spectra and fluorescence spectra characterization showed that the aqueous solution of this complex showed the characteristic absorption and emission peaks of bisotiazole at 292 and 412 nm.