[Er(nmp)4(H2O)3]H[SiMo12O40] 2nmp 0.5H2O的合成、性质与晶体结构

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由Er2O3、H4SiMo12O40和nmp合成了分子组成为[Er(nmp)4(H2O)3]H[SiMo12O40]2nmp0.5H2O(nmp=N-甲基吡咯烷酮)的配合物,并通过单晶X-射线衍射测定了晶体结构。结果表明,该化合物属单斜晶系,P21/c空间群,晶胞参数a=17.4601(7),b=18.1906(5),c=22.9096(8)?b=105.2980(10),Z=4,V=7018.5(4)3,Dc=2.504g/cm3,R=0.0460,wR=0.1114,F(000)=5064.配合物中Er3+以七配位的单加冠三棱柱构型配阳离子形式存在,与之配位的是4个N-甲基吡咯烷酮和3个H2O分子,该配阳离子与[SiMo12O40]4-阴离子通过静电作用相结合。 The complex of [Er (nmp) 4 (H2O) 3] H [SiMo12O40] 2nmp0.5H2O (nmp = N-methylpyrrolidone) was synthesized from Er2O3, H4SiMo12O40 and nmp and characterized by single crystal X-ray diffraction The crystal structure was measured. The results show that the compound belongs to the monoclinic space group P21 / c with unit cell parameters of a = 17.4601 (7), b = 18.1906 (5), c = 22.9096 (8) b = 105.2980 4, V = 7018.5 (4) 3, Dc = 2.504g / cm3, R = 0.0460, wR = 0.1114 and F (000) = 5064. The Er3 + With 4 N-methylpyrrolidone and 3 H2O molecules coordinated with [SiMo12O40] 4-anions via electrostatic interaction.
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