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通过引种试验 ,对鲁梅克斯 K- 1杂交酸模的生长发育规律、营养成分、耐盐力等进行了研究。结果表明 ,该杂交酸模在肥水充足的条件下 ,营养价值高 ,蛋白质含量高达 2 0 %～ 38% ;繁殖力强 ,一年可刈割 4茬～ 5茬 ,每公顷收获鲜草 1 50 t左右。按照抗逆半衰减定义 ,该牧草耐盐力为 0 .32 5% ,只能抗中等盐碱。但收获携盐能力较强 ,从平均盐离子含量来看 ,每种植 1 hm2鲁梅克斯 ,通过牧草收割 ,一年可携走土壤中的盐分 1 50 kg～ 2 0 0 kg
Through the introduction test, the growth and development regularity, nutrition composition, salt tolerance of Rumex K-1 hybrid model were studied. The results showed that the hybrid model had high nutritional value and high protein content of 20% -38% under the conditions of adequate fertilizer and water. It had a strong fertility and could cut 4 to 5 stubbles a year, and the yield of fresh grass per hectare was 1 50 t about. According to the definition of resistance to half-attenuation, the forage salt tolerance is 0.32 5%, only anti-moderate saline. However, the harvested salt is more capable of harvesting salt. From the average salt ion content, 1 hm2 of Rumex per plant can be harvested by forage harvest and the salt content in the soil can be removed for one year. 50 kg to 200 kg