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正弦曲线y=Asin(ωx+(?))具有对称性,它的对称轴过曲线的最高(低)点,故由ωx+(?)=kπ+π/2,可得对称轴方程是1/x=1/ω(kπ+π/2-(?))(k∈Z).下面通过往年一道高考题的解法探寻,来体会处理对称问题的若干思考方向.
The sine curve y=Asin(ωx+(?)) has symmetry. Its symmetry axis crosses the highest (low) point of the curve, so from ωx+(?)=kπ+π/2, the symmetry axis equation is 1/x =1/ω(kπ+π/2-(?))(k∈Z). We will explore some directions for dealing with symmetry by following the solution of a college entrance examination question in previous years.