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有机化合物数目众多,其原因之一是有机物的异构现象。例如,丁烷(C_4H_(10))有两个异构体,辛烷(C_8H_(18))有18个,十五烷(C(15)H(32))有4347个,而二十烷(C_(20)H_(42))则有366319个。这些烷烃的异构体数是如何求得呢?本文介绍用“逐个计算法”来求一元烷醇和烷烃的异构体数。为便于读者理解文中某些公式,首先介绍了三个基本汁算公式。随后详细介绍异构体数的计算方法。鉴于异构体数的计算庞杂,又易出错,本文数据是用电子计算机计算的,这样可以极为迅速而准确地得到计算结果。
A large number of organic compounds, one of the reasons for the heterogeneous phenomenon of organic matter. For example, there are two isomers of butane (C_4H_ (10)), with 18 octane (C_8H_ (18)) and 4347 pentadecane (C (15) H (C_ (20) H_ (42)) there are 366,319. How can these isomers be obtained? The article describes the calculation of the number of isomers of monovalent alkanols and alkanes using the “one by one” method. In order to facilitate readers to understand some of the formulas in the paper, first introduced three basic juice calculation formula. Then detailed description of the calculation method of the number of isomers. In view of the complex calculation of the number of isomers, but also prone to error, the data in this paper is calculated using a computer, so that the results can be very quickly and accurately calculated.