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文[1]给出了如何辨别函数y=3logax(a>0,a≠1)是不是对数函数的两种方法,阐明了函数y=3logax(a>0,a≠1)是对数函数,虽然有些道理,但是我们认为这个结论不十分妥当.要回答函数y=3logax(a>0,a≠1)是不是对数函数,首先必须回答以下两个问题,第一个问题是对数函数定义的真正含义是什么;第二个问题是有多少个对数函数.
In [1], two methods are given to determine whether the function y = 3logax (a> 0, a ≠ 1) is a logarithmic function. It is clarified that the function y = 3logax (a> 0, a ≠ 1) Function, though it makes some sense, but we do not think this conclusion is appropriate.If we want to answer whether the function y = 3logax (a> 0, a ≠ 1) is a logarithmic function, we must first answer the following two questions. The first question is about What is the true meaning of a function definition? The second question is how many logarithmic functions are there.