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3.7拱肋中,拱頂处水平推力影响綫 如以前在2.4节所述,使中央节間拱肋的拱頂处产生单位軸向位移,首先要把整个体系变为一个簡文体系,在此体系中产生这样一个相对位移,最簡便的方法見表6。将下弦杆GH假定在G,H点暫时与整个体系的其余部份分开,分別在R,S处各产生相等而相反的轉动,φ=1/2h,及φ=-1/2h。其中h为中央节問的高度=2.25′。又假設在下弦杆GH的G,H点分別轉动同一轉角,可以看得出左边四个节間将如一个刚体繞R点轉动φ角,而右边四个节間将繞S点轉动負角度-φ。在簡支的情况下这种轉动是可能的,除中央节間的弦杆外不会有弯矩产生。研究空腹拱的变形曲綫
3.7 Arch Ribs, the influence line of horizontal thrust at vaults As previously described in Section 2.4, unit axial displacements occur at the vaults of the central interna rib arch, first of all the entire system should be transformed into a simple text system in which The easiest way to generate such a relative displacement in the system is shown in Table 6. The lower chord GH is assumed to be momentarily separated from the rest of the system at points G and H, with equal and opposite rotations at R and S respectively, φ = 1 / 2h and φ = -1 / 2h. Where h is the height of the central node = 2.25 ’. Assuming that the G and H points of the lower chord GH rotate by the same rotation angle respectively, it can be seen that the left four inverses will be rotated by one angle φ around a point R and the right four internals will rotate around the point S Negative angle-φ. In the simple case of this rotation is possible, in addition to the central internals outside the chord will not have a bending moment. Study the deformation curve of fasting arch