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2009年高考全国卷Ⅱ第9题:直线y=k(x+2)(k>0)与抛物线y2=8x相交于A、B两点,F是抛物线的焦点,若|FA|=2|FB|,求k的值(以下简称问题)。
2009 National Entrance Examination Ⅱ 9 Problem 9: The line y = k (x + 2) (k> 0) intersects the parabola y2 = 8x at points A and B. F is the focal point of the parabola. If | FA | = 2 | FB |, find the value of k (hereinafter referred to as the problem).