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该文考虑多滞量和正负系数中立型方程[x(t)-sum from n=1 to l(1/n)C<sub>A</sub>(t)x(t-r<sub>n</sub>)]+sum from i=1 to (1/i)P<sub>i</sub>(t)x()t-τ<sub>i</sub>)-sum from j=1 to n(1/j)Q<sub>j</sub>(t)x(t-σ<sub>j&l