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2011年全国高中数学联赛吉林赛区预赛第3题:设函数y=f(x)(x∈R)满足f(x+2)=f(x),且当x∈(-1,1]时,f(x)=1-x2,函数g(x)=lg︱x︱,x≠0,1,x=0.则函数t(x)=f(x)-g(x)在区间[-5,10]内零点的个数为()
2011 3rd National High School Mathematical Olympiad Jilin Division Preliminary Question 3: Let the function y = f (x) (x∈R) satisfy f (x + 2) = f (x) , the function t (x) = f (x) -g (x) in the interval [ -5,10] the number of zero points ()