论文部分内容阅读
一、要点解读1.复数的加法:设z_1=a+bi,z_2=c+di(a,b,c,d∈R)是任意的两个复数,则z_1+z_2=(a+bi)+(c+di)=(a+c)+(b+d)i。复数的和仍然为一个复数,其实部为z_1、z_2的实部和,虚部为z_1、z_2的虚部和。复数加法满足:(1)交换律:z_1+z_2=z_2+z_1;(2)结合律:(z_1+z_2)+z_3=z_1+(z_2+z_3)。2.复数的减法:(加法的逆运算)复
First, the point of interpretation 1. Complex addition: Let z_1 = a + bi, z_2 = c + di (a, b, c, d∈R) is an arbitrary two complex numbers, then z_1 + z_2 = (a + bi) + (c + di) = (a + c) + (b + d) i. The complex number is still a complex number, the real part is the real part of z_1, z_2, and the imaginary part is the imaginary part of z_1, z_2. The complex addition satisfies: (1) Exchange law: z_1 + z_2 = z_2 + z_1; (2) The combination law: (z_1 + z_2) + z_3 = z_1 + (z_2 + z_3). 2. Subtraction of complex numbers: (addition of the inverse operation) complex