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近年来,数列与导数交汇的试题,倍受命题者的青睐.这类试题通常将函数不等式与数列不等式相联系,若能发现、用好这种联系,并有效转化,也就牵住了这类试题的“牛鼻子”.可按照“寻找交汇,换元转化”的思路分析求解,介绍如下.一、问题对接,换元转化在数列与导数交汇题中,通常会由多个小问题组成,若数列相应问题与前一个函数问题都包含了对数不等式或指数不等式,则通过问题对接,运用换元转化,可将函数不等
In recent years, the series of questions and the intersection of the test questions, much propositional favor.This type of test questions usually function inequalities and numerical inequalities associated, if we can find that make good use of this link, and effective conversion, also hold on to this Class questions “cow nose ” can be in accordance with “find convergence, change yuan into ” train of thought analysis, introduced as follows: First, the problem of docking, transformation of yuan In the series and derivative of the confluence, usually by more than one If there are logarithmic inequality or exponential inequality, if the corresponding problem of the series and the previous one contain the inequality of logarithms or exponents, the functions can be varied