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题目已知角a的补角是 132°18′42″,试求∠a的余角。解∵∠a的补角是132°18′42″, ∴∠a=180°-132°18′42″=179°59′60″-132°18′42″=47°41′18″。故∠a的余角=90°-47°41′18″=89°59′60″-47°41′18″=42°18′42″。
The topic is known as the angle a of which is 132°18′42′′. Try to find the complement of ∠a. The complement of ∵∠a is 132°18′42′′, ∴∠a=180°-132°18′. 42′′=179°59′60′′-132°18′42′′=47°41′18′′. Therefore, the remaining angle of ∠a=90°-47°41′18′′=89°59′60′′-47°41′18′′=42°18′42′′.