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每个操作过拖拉机从事过农田作业的机手,都一定对连结拖拉机和农机具的传动轴十分熟悉,这个宝贵疙瘩工作时的不配合,曾使很多机手大伤脑筋,恨的牙根疼,有的机手一个短短的20多天作业季下来,竟然损坏三四个。费钱不说,关键是还耽误很多时间,影响创收,究竟应如何使用和维修传动轴呢?1了解传动轴的工作原理及结构首先,我们应该清楚,传动轴是用来传递发动机功率的,在这里发动机的功率可用公式N=FV来表示,由这个公式可以看出:当拖拉机输出功率一定的情况下,要使拖拉机所带农具的转速增加,那么其扭矩一定不能太大。如:拖拉机所带秸秆还田机,其刀轴转速要求2 000 r/min左右,而拖拉机额定输出转速为定值,一般大型轮式拖拉机后动力输出轴转速为760 r/min,中小型轮拖为540 r/min;现在又出现双动力输出760 r/min,1 000 r/min(储备转速);760 r/min,850 r/min。因此秸
Every tractor has been engaged in agricultural operations of the hands, must be on the tractor and farm machinery with the transmission shaft is very familiar with the work of this valuable pimple does not cooperate, has caused a lot of big hand-brains, hate the root pain, Some machines a short span of more than 20 days operating season down, even three or four damaged. Cost is not to say, the key is to delay a lot of time, affecting revenue, how to use and repair drive shaft it? 1 understand the working principle and structure of the drive shaft First of all, we should be clear that the drive shaft is used to transmit engine power, Here the power of the engine can be expressed by the formula N = FV. It can be seen from this formula that when the output power of the tractor is constant, the torque of the tractor must not increase too much to increase the rotating speed of the farm implements. Such as: tractors with straw machine, the knife shaft speed of about 2000 r / min, while the tractor rated output speed is constant, the general large wheeled tractor power output shaft speed of 760 r / min, small and medium-sized round Drag to 540 r / min; Now there are two power output 760 r / min, 1 000 r / min (reserve speed); 760 r / min, 850 r / min. So straw