论文部分内容阅读
贵刊 2 0 0 1年第 1期的有奖解题擂台 ( 47)为题 在△ＡＢＣ中 ,证明或否定不等式 :4 02 7ｓｉｎＡｓｉｎＡ +ｓｉｎＢ +ｓｉｎＢｓｉｎＢ +ｓｉｎＣ +ｓｉｎＣｓｉｎＣ +ｓｉｎＡ 4 12 7 ①显然 ,不等式①试图加强下列不等式。1 39ａａ +ｂ+ｂｂ +ｃ+ｃｃ+ａ1 49②(《数
The prize-solving questions in the first issue of your magazine in year 2010 (47) is titled in △ABC. Proof or negation inequality: 4 02 7sinAsinA +sinB +sinBsinB +sinC +sinCsinC +sinA 4 12 7 1 Obviously, Inequality 1 attempts to reinforce the following inequality. 1 39aa +b+bb +c+cc+a1 492 (number