用函数观点解决“牛吃草”问题(初一)

• 作 者: 王金钟 周奕生
• 机 构: 福建省南安市教师进修学校,福建省安溪县虎邱安溪15中学,
• 出 处: 数理天地(初中版)
• 发表日期: 2016年10期
• 关键词: 函数式 水库水位 水位降 水位高度 内使 正整数 天可 牛时 请看 上草

杰出的物理学家牛顿,也是一位数学家,他曾经出了这样一道有名的“牛吃草”问题:一块草地,草每天都在均匀地生长.如果放牧27头牛,6周刚好吃完;如果放牧23头牛,9周刚好吃完.问:如果放牧21头牛,那么几周刚好吃完?此题的解法很多,本文介绍函数观点解法.设:草地上原有的草量是m、草每周生长出来的草量是n,每头牛每周的吃草量是p;放牧的牛数是x头,牛吃完草的周数是y,则得

Outstanding physicist Newton, also a mathematician, has come out with such a famous “cow grazing” problem: a meadow where grass grows evenly every day, and if grazing 27 cattle, 6 weeks ago If you graze 23 cattle, 9 weeks just finished eating. Q: If the grazing of 21 cattle, then just eat a few weeks? This problem a lot of solutions, this article introduces the functional point of view solution. Of the grass is m, the grass grows out of the grass every week is n, each cow’s grazing weekly is p; grazing cattle is the first x, the number of weeks after the grass is y