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在匀变速直线运动中,相邻两个连续相等的时间里的位移差等于恒量,即Δs=aT2。笔者认为教学中可提出“Δs=aT2适用于平抛运动吗”供学生讨论,普遍认为Δs=aT2不适用于平抛运动。现对此问题进行探讨,供同行参考。 设以初速度v0水平抛出(a=g)的物体,第1s内、第2s内、……第ns内的位移分别为s1、s2、……sn。将位移分解为水平方向和竖直方向的两个分位移,则第1s内的位移s→1=x→1+y→1。第2s内的位移s→2=x→2+y→2。
In uniform linear motion, the displacement difference between adjacent two consecutive equal times is equal to the constant, that is, Δs=aT2. The author believes that “Δs=aT2 is suitable for flat throwing exercise” can be proposed in the teaching for students to discuss. It is generally believed that Δs=aT2 does not apply to flat throwing exercise. This issue is now discussed for reference by peers. Let the object thrown (a=g) horizontally at the initial velocity v0 be within s1, s2, ... sn within the first s, the second s, the ... ns. The displacement is decomposed into two sub-displacements in the horizontal and vertical directions. The displacement in the first s→1=x→1+y→1. The displacement in the second s→2=x→2+y→2.