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由于-1+m≤sinx+m≤1+m,可分段讨论,结果如下表:可类似讨论y=α(cosx+m)~2+n的极值问题。例.子函数y=cos~2x+2
Since -1+m≤sinx+m≤1+m, it can be discussed in sections. The results are shown in the following table: The problem of the extreme value of y=α(cosx+m)~2+n can be similarly discussed. Example. Subfunction y=cos~2x+2