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今天听了一节试卷分析课,感受很深,现将所听的一道题的感受与大家分享。已知数列{an}、{bn}都是公差为1的等差数列,其首项分别为a1、b1,且a1+b1=5,a1、b1∈N+。设cn=abn(n∈N+),则数列{cn}的前10项和等于()A.55 B.70 C.85 D.100本题昨天和学生一起做了,当时对题意理解不是很到位,感觉无法下手,没有具体的思路,纠结了一会儿,我先放弃了本题,
Today, listening to a test paper analysis class, I feel very deep, now I heard the feeling of a question to share with you. It is known that the {an} and {bn} are all arithmetic sequences with a tolerance of 1, the first term is a1, b1, and a1 + b1 = 5, a1, b1∈N +. Let cn = abn (n ∈ N +), then the first ten items of {cn} and equal to () A.55 B.70 C.85 D.100 The question was done with the students yesterday and was not very understanding In place, I feel unable to start, there is no specific way of thinking, tangled for a while, I first gave up the problem,