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题目如图1,两水平面(虚线)之间的距离为H,其间的区域存在方向水平向右的匀强电场。自该区域上方的A点将质量为m、电荷量分别为q和-q(q>0)的带电小球M、N先后以相同的初速度沿平行于电场的方向射出。小球在重力作用下进入电场区域,并从该区域的下边界离开。已知N离开电场时的速度方向竖直向下;M在电场中做直线运动,刚离开电场时的动能为N刚离开电场时动能的1.5倍。
The subject is shown in Fig. 1, the distance between two horizontal planes (dashed line) is H, and there is a uniform electric field in the horizontal direction to the right. From the point A above the region, charged pellets M of mass m, electric charges q and -q (q> 0), respectively, are emitted at a same initial velocity in the direction parallel to the electric field. The pellets enter the electric field area under the force of gravity and leave from the lower boundary of the area. It is known that the velocity direction of N leaves the electric field vertically downward; M makes a linear motion in the electric field, the kinetic energy just leaving the electric field is 1.5 times of the kinetic energy of N just leaving the electric field.