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自然数的k(k∈N*)次等幂和,即Sk(n)=1k+…+nk的求和,文[1]已给出多种方法,由文[1]的方法,我们容易求得:
The sum of powers of natural numbers k (k∈N *), ie the summation of Sk (n) = 1k + ... + nk, has been given in many papers [1] Too: