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答:配制葡萄糖大输液,有时会由于原料关系使配成的溶液中含有胶体粒子而影响澄明度,有人用电泳实验证明带有负电粒子,因此可以加入适量的电解质以中和粒子的电荷,使胶粒凝聚加大,而被砂棒滤掉。氯化钠是一种电解质,含单价正离子,可中和胶体粒子上的负电荷,使胶粒凝聚加大而被滤除。根据有关资料,在每1000ml 葡萄糖溶液中(5～25%)加入0.26g 氯化钠,即可除掉胶体物,以保证输液澄明度
A: The preparation of glucose infusion, and sometimes due to the relationship between the raw materials to make the solution containing colloidal particles and affect clarity, it was electrophoresis experiments with negative particles, so you can add the right amount of electrolyte to neutralize the charge of the particles so that Gel aggregation increases, but was filtered out of the sand bar. Sodium chloride is an electrolyte containing monovalent cations that neutralize the negative charges on the colloidal particles and cause them to coalesce and become filtered out. According to the information, in each 1000ml glucose solution (5 ~ 25%) by adding 0.26g of sodium chloride, you can get rid of colloidal substances in order to ensure the clarity of the infusion